What are the solutions to the equation r^3+5r^2+8r+4=0 ?

The solutions to the equation r^3+5r^2+8r+4=0 are r=-1,r=-2

Find the zeros of r^3+5r^2+8r+4=0

The zeros of r^3+5r^2+8r+4=0 are r=-1,r=-2

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r^{3} + 5 r^{2} + 8 r + 4 = 0

r = - 1, r = - 2

Solution steps

r^{3} + 5 r^{2} + 8 r + 4 = 0

Factor

r^{3} + 5 r^{2} + 8 r + 4 : (r + 1) (r + 2)^{2}

(r + 1) (r + 2)^{2} = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

r + 1 = 0 or r + 2 = 0

Solve

r + 1 = 0 : r = - 1

Solve

r + 2 = 0 : r = - 2

The solutions are

r = - 1, r = - 2

5 x^{3} - 2 x^{2} + 20 x - 8

64 x^{3} = 1

z^{4} = - 2 + 0 i

x^{3} - 4 x^{2} + 5 x - 2

4 x^{3} - 16 = 0

What are the solutions to the equation r^3+5r^2+8r+4=0 ?
The solutions to the equation r^3+5r^2+8r+4=0 are r=-1,r=-2
Find the zeros of r^3+5r^2+8r+4=0
The zeros of r^3+5r^2+8r+4=0 are r=-1,r=-2