What is the answer to 1-1/(3t^{2/3)}=0 ?

The answer to 1-1/(3t^{2/3)}=0 is t= 1/(3sqrt(3)),t=-1/(3sqrt(3))

Solve for t: 1-1/(3t^{2/3)}=0

The solution is t= 1/(3sqrt(3)),t=-1/(3sqrt(3))

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1 - \frac{1}{3 t ^{\frac{2}{3}}} = 0

t = \frac{1}{3 3}, t = - \frac{1}{3 3}

Decimal

t = 0.19245 \dots, t = - 0.19245 \dots

Solution steps

1 - \frac{1}{3 t ^{\frac{2}{3}}} = 0

Multiply both sides by

3 t^{\frac{2}{3}}

1 \cdot 3 t^{\frac{2}{3}} - \frac{1}{3 t ^{\frac{2}{3}}} \cdot 3 t^{\frac{2}{3}} = 0 \cdot 3 t^{\frac{2}{3}}

Simplify

3 t^{\frac{2}{3}} - 1 = 0

Move

1

to the right side

3 t^{\frac{2}{3}} = 1

Divide both sides by

3

t^{\frac{2}{3}} = \frac{1}{3}

Take both sides of the equation to the power of

3 : t^{2} = \frac{1}{27}

t^{2} = \frac{1}{27}

Solve

t^{2} = \frac{1}{27} : t = \frac{1}{3 3}, t = - \frac{1}{3 3}

t = \frac{1}{3 3}, t = - \frac{1}{3 3}

Verify Solutions:

t = \frac{1}{3 3}

True

, t = - \frac{1}{3 3}

True

The solutions are

t = \frac{1}{3 3}, t = - \frac{1}{3 3}

5 x + 34 = x + 8

16 - 4 x = 6

3 x^{\frac{2}{3}} - 2 x = 0

3 x + 12 = \frac{x + 5}{3}

x + 25 + 5 = x

What is the answer to 1-1/(3t^{2/3)}=0 ?
The answer to 1-1/(3t^{2/3)}=0 is t= 1/(3sqrt(3)),t=-1/(3sqrt(3))
Solve for t: 1-1/(3t^{2/3)}=0
The solution is t= 1/(3sqrt(3)),t=-1/(3sqrt(3))