What is the answer to 5+2x=sqrt(x^2-2x+1) ?

The answer to 5+2x=sqrt(x^2-2x+1) is x=-4/3

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5+2x=sqrt(x^2-2x+1)

5 + 2 x = x^{2} - 2 x + 1

x = - \frac{4}{3}

Decimal

x = - 1.33333 \dots

Solution steps

5 + 2 x = x^{2} - 2 x + 1

Square both sides:

25 + 20 x + 4 x^{2} = x^{2} - 2 x + 1

25 + 20 x + 4 x^{2} = x^{2} - 2 x + 1

Solve

25 + 20 x + 4 x^{2} = x^{2} - 2 x + 1 : x = - \frac{4}{3}, x = - 6

x = - \frac{4}{3}, x = - 6

Verify Solutions:

x = - \frac{4}{3}

True

, x = - 6

False

The solution is

x = - \frac{4}{3}

4 + x + 5 = 0

x + 2 - x - 6 = 2

x^{\frac{1}{4}} + 3 = 0

2 - 7 x^{2} - \frac{1}{4} = \frac{x}{2}

12 = - 6 b + 4

What is the answer to 5+2x=sqrt(x^2-2x+1) ?
The answer to 5+2x=sqrt(x^2-2x+1) is x=-4/3
Solve for x: 5+2x=sqrt(x^2-2x+1)
The solution is x=-4/3