What is the answer to (-2x^2+64)/(sqrt(64-x^2))=0 ?

The answer to (-2x^2+64)/(sqrt(64-x^2))=0 is x=4sqrt(2),x=-4sqrt(2)

Solve for x: (-2x^2+64)/(sqrt(64-x^2))=0

The solution is x=4sqrt(2),x=-4sqrt(2)

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\frac{- 2 x ^{2} + 64}{64 - x ^{2}} = 0

x = 42, x = - 42

Decimal

x = 5.65685 \dots, x = - 5.65685 \dots

Solution steps

\frac{- 2 x ^{2} + 64}{64 - x ^{2}} = 0

\frac{f ( x )}{g ( x )} = 0 \Rightarrow f (x) = 0

- 2 x^{2} + 64 = 0

Solve

- 2 x^{2} + 64 = 0 : x = 42, x = - 42

x = 42, x = - 42

Verify Solutions:

x = 42

True

, x = - 42

True

The solutions are

x = 42, x = - 42

2 - 4 - (x + 1)^{2}

\frac{1}{1 - 5 x} = \frac{1}{6}

x - 2 + x - 4 = 2 x - 2

2 x - 2 - x - 5 + 1 = 0

x + 5 + 18 = 19

What is the answer to (-2x^2+64)/(sqrt(64-x^2))=0 ?
The answer to (-2x^2+64)/(sqrt(64-x^2))=0 is x=4sqrt(2),x=-4sqrt(2)
Solve for x: (-2x^2+64)/(sqrt(64-x^2))=0
The solution is x=4sqrt(2),x=-4sqrt(2)