What is the answer to sqrt(18x^2-6x+1)=3x ?

The answer to sqrt(18x^2-6x+1)=3x is x= 1/3

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sqrt(18x^2-6x+1)=3x

18 x^{2} - 6 x + 1 = 3 x

x = \frac{1}{3}

Decimal

x = 0.33333 \dots

Solution steps

18 x^{2} - 6 x + 1 = 3 x

Square both sides:

18 x^{2} - 6 x + 1 = 9 x^{2}

18 x^{2} - 6 x + 1 = 9 x^{2}

Solve

18 x^{2} - 6 x + 1 = 9 x^{2} : x = \frac{1}{3}

x = \frac{1}{3}

Verify Solutions:

x = \frac{1}{3}

True

The solution is

x = \frac{1}{3}

14 x + 2 + 18 = 8

2 x^{\frac{1}{2}} - x^{\frac{1}{4}} - 1 = 0

x + 4 + 7 = 5

3 x - 5 = x - 3

- 5 = 4 (6 x + 3)^{3} - 32

What is the answer to sqrt(18x^2-6x+1)=3x ?
The answer to sqrt(18x^2-6x+1)=3x is x= 1/3
Solve for x: sqrt(18x^2-6x+1)=3x
The solution is x= 1/3