What is the answer to 4b^{-3/4}+10= 21/2 ?

The answer to 4b^{-3/4}+10= 21/2 is b=16

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4b^{-3/4}+10= 21/2

4 b^{- \frac{3}{4}} + 10 = \frac{21}{2}

b = 16

Solution steps

4 b^{- \frac{3}{4}} + 10 = \frac{21}{2}

Multiply both sides by

2

4 b^{- \frac{3}{4}} \cdot 2 + 10 \cdot 2 = \frac{21}{2} \cdot 2

Simplify

8 b^{- \frac{3}{4}} + 20 = 21

Expand

8 b^{- \frac{3}{4}} + 20 : \frac{8}{b ^{\frac{3}{4}}} + 20

\frac{8}{b ^{\frac{3}{4}}} + 20 = 21

Remove roots

\frac{4096}{b ^{3}} = 1

Solve

\frac{4096}{b ^{3}} = 1 : b = 16

b = 16

Verify Solutions:

b = 16

True

The solution is

b = 16

x + 3 = 4 x + 12

12 x - 12 - x = - 1

- 3 + 3 x = 6

4 x + 2 - 2 x - 4 = 0

x + 17 = - 4

What is the answer to 4b^{-3/4}+10= 21/2 ?
The answer to 4b^{-3/4}+10= 21/2 is b=16
Solve for b: 4b^{-3/4}+10= 21/2
The solution is b=16