What is the answer to sqrt(2x+1)+sqrt(x-3)=2sqrt(x) ?

The answer to sqrt(2x+1)+sqrt(x-3)=2sqrt(x) is x=4

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sqrt(2x+1)+sqrt(x-3)=2sqrt(x)

2 x + 1 + x - 3 = 2 x

x = 4

Solution steps

2 x + 1 + x - 3 = 2 x

Remove square roots

8 x^{2} - 20 x - 12 = x^{2} + 4 x + 4

Solve

8 x^{2} - 20 x - 12 = x^{2} + 4 x + 4 : x = 4, x = - \frac{4}{7}

x = 4, x = - \frac{4}{7}

Verify Solutions:

x = 4

True

, x = - \frac{4}{7}

False

The solution is

x = 4

x - 3 x - 1 + 1 = 0

2 x - 4 + 2 = 3 x + 4

6 x + 7 = 7 x + 7 + 6

2 - x = 2 - x^{2}

\frac{x}{x + 1 + 1} = x + 1 - 1

What is the answer to sqrt(2x+1)+sqrt(x-3)=2sqrt(x) ?
The answer to sqrt(2x+1)+sqrt(x-3)=2sqrt(x) is x=4
Solve for x: sqrt(2x+1)+sqrt(x-3)=2sqrt(x)
The solution is x=4