What is the answer to \sqrt[3]{3y+6}+7=8 ?

The answer to \sqrt[3]{3y+6}+7=8 is y=-5/3

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\sqrt[3]{3y+6}+7=8

3 3 y + 6 + 7 = 8

y = - \frac{5}{3}

Decimal

y = - 1.66666 \dots

Solution steps

3 3 y + 6 + 7 = 8

Move

7

to the right side

3 3 y + 6 = 1

Take both sides of the equation to the power of

3 : 3 y + 6 = 1

3 y + 6 = 1

Solve

3 y + 6 = 1 : y = - \frac{5}{3}

y = - \frac{5}{3}

Verify Solutions:

y = - \frac{5}{3}

True

The solution is

y = - \frac{5}{3}

2 x - 5 = 4 x - 7

12 - a + 7 a = 8 a

x^{- \frac{1}{3}} = \frac{3}{2}

1 - x - 13 + x = x + 4

y, x + y = 45

What is the answer to \sqrt[3]{3y+6}+7=8 ?
The answer to \sqrt[3]{3y+6}+7=8 is y=-5/3
Solve for y: \sqrt[3]{3y+6}+7=8
The solution is y=-5/3