What is the answer to sqrt(6+x-x^2)=1-x ?

The answer to sqrt(6+x-x^2)=1-x is x=-1

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sqrt(6+x-x^2)=1-x

6 + x - x^{2} = 1 - x

x = - 1

Solution steps

6 + x - x^{2} = 1 - x

Square both sides:

6 + x - x^{2} = 1 - 2 x + x^{2}

6 + x - x^{2} = 1 - 2 x + x^{2}

Solve

6 + x - x^{2} = 1 - 2 x + x^{2} : x = - 1, x = \frac{5}{2}

x = - 1, x = \frac{5}{2}

Verify Solutions:

x = - 1

True

, x = \frac{5}{2}

False

The solution is

x = - 1

x - 3 = 9

4 x - 2 = 9 x + 7

0 = - \frac{2}{3} x^{- \frac{1}{3}}

2 x + 1 + 2 = 4 x + 9

\frac{x - 2}{4} + 9 \frac{x - 2}{4} = 10

What is the answer to sqrt(6+x-x^2)=1-x ?
The answer to sqrt(6+x-x^2)=1-x is x=-1
Solve for x: sqrt(6+x-x^2)=1-x
The solution is x=-1