What is the answer to sqrt(x^2+4x+4)=1 ?

The answer to sqrt(x^2+4x+4)=1 is x=-1,x=-3

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sqrt(x^2+4x+4)=1

x^{2} + 4 x + 4 = 1

x = - 1, x = - 3

Solution steps

x^{2} + 4 x + 4 = 1

Square both sides:

x^{2} + 4 x + 4 = 1

x^{2} + 4 x + 4 = 1

Solve

x^{2} + 4 x + 4 = 1 : x = - 1, x = - 3

x = - 1, x = - 3

Verify Solutions:

x = - 1

True

, x = - 3

True

The solutions are

x = - 1, x = - 3

4 2 x - 2 = 2

2 + x = 2 x + 8

2 3 7 - 3 x - 3 = - 7

\frac{1}{2} x - 11 = 3 x + 9 - 18

x \times x + 7 = 6

What is the answer to sqrt(x^2+4x+4)=1 ?
The answer to sqrt(x^2+4x+4)=1 is x=-1,x=-3
Solve for x: sqrt(x^2+4x+4)=1
The solution is x=-1,x=-3