What is the answer to sqrt(x^2-5x+1)-sqrt(1-8x)=0 ?

The answer to sqrt(x^2-5x+1)-sqrt(1-8x)=0 is x=0,x=-3

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sqrt(x^2-5x+1)-sqrt(1-8x)=0

x^{2} - 5 x + 1 - 1 - 8 x = 0

x = 0, x = - 3

Solution steps

x^{2} - 5 x + 1 - 1 - 8 x = 0

Remove square roots

x^{2} - 5 x + 1 = 1 - 8 x

Solve

x^{2} - 5 x + 1 = 1 - 8 x : x = 0, x = - 3

x = 0, x = - 3

Verify Solutions:

x = 0

True

, x = - 3

True

The solutions are

x = 0, x = - 3

6 + 3 y - 4 = 9

x - 2 - 1 = 3 - x

3 3 x + 4 - x = 5 + x

6 + \frac{6}{x ^{\frac{5}{11}}} = 0

2 2 x - 8 = 3 (2 x + 2)

What is the answer to sqrt(x^2-5x+1)-sqrt(1-8x)=0 ?
The answer to sqrt(x^2-5x+1)-sqrt(1-8x)=0 is x=0,x=-3
Solve for x: sqrt(x^2-5x+1)-sqrt(1-8x)=0
The solution is x=0,x=-3