What is the answer to solvefor x,ln(y)=mln(x)+ln(b) ?

The answer to solvefor x,ln(y)=mln(x)+ln(b) is x=e^{(ln(y)-ln(b))/m}

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solvefor x,ln(y)=mln(x)+ln(b)

solve for

x, ln (y) = m ln (x) + ln (b)

x = e^{\frac{l n ( y ) - l n ( b )}{m}}

Solution steps

ln (y) = m ln (x) + ln (b)

Switch sides

m ln (x) + ln (b) = ln (y)

Move

ln (b)

to the right side

m ln (x) = ln (y) - ln (b)

Divide both sides by

m

ln (x) = \frac{ln ( y ) - ln ( b )}{m}

Apply log rules

x = e^{\frac{l n ( y ) - l n ( b )}{m}}

x, y = ln (x)

lo g_{10} (2 x) = 3

x^{l o g_{10} (x)} = 100 x

lo g_{a} (x)

lo g_{10} (x + 5) = 1.2

What is the answer to solvefor x,ln(y)=mln(x)+ln(b) ?
The answer to solvefor x,ln(y)=mln(x)+ln(b) is x=e^{(ln(y)-ln(b))/m}