What is the answer to log_{10}(x-2)+log_{10}(12-x)=0 ?

The answer to log_{10}(x-2)+log_{10}(12-x)=0 is x=7-2sqrt(6),x=7+2sqrt(6)

Solve for x: log_{10}(x-2)+log_{10}(12-x)=0

The solution is x=7-2sqrt(6),x=7+2sqrt(6)

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lo g_{10} (x - 2) + lo g_{10} (12 - x) = 0

x = 7 - 26, x = 7 + 26

Decimal

x = 2.10102 \dots, x = 11.89897 \dots

Solution steps

lo g_{10} (x - 2) + lo g_{10} (12 - x) = 0

Apply log rules

(x - 2) (12 - x) = 1

Solve

(x - 2) (12 - x) = 1 : x = 7 - 26, x = 7 + 26

x = 7 - 26, x = 7 + 26

Verify Solutions:

x = 7 - 26

True

, x = 7 + 26

True

The solutions are

x = 7 - 26, x = 7 + 26

lo g_{x} (25) = 4

lo g_{10} (x) = 3

lo g_{2} (4 - x) = 7

ln (x) = 5

lo g_{2} (X + 2) + lo g_{2} (X - 1) = 2

What is the answer to log_{10}(x-2)+log_{10}(12-x)=0 ?
The answer to log_{10}(x-2)+log_{10}(12-x)=0 is x=7-2sqrt(6),x=7+2sqrt(6)
Solve for x: log_{10}(x-2)+log_{10}(12-x)=0
The solution is x=7-2sqrt(6),x=7+2sqrt(6)