What is the answer to -7+log_{3}(4-x)=-6 ?

The answer to -7+log_{3}(4-x)=-6 is x=1

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-7+log_{3}(4-x)=-6

- 7 + lo g_{3} (4 - x) = - 6

x = 1

Solution steps

- 7 + lo g_{3} (4 - x) = - 6

Move

7

to the right side

lo g_{3} (4 - x) = 1

Apply log rules

4 - x = 3

Solve

4 - x = 3 : x = 1

x = 1

Verify Solutions:

x = 1

True

The solution is

x = 1

lo g_{10} (x) + lo g_{10} (8) = 2

lo g_{2} (a) = 10

ln (x) = e

2 lo g_{10} (x) = lo g_{10} (2) + lo g_{10} (3 x - 4)

a, lo g_{a} (b) = c

What is the answer to -7+log_{3}(4-x)=-6 ?
The answer to -7+log_{3}(4-x)=-6 is x=1
Solve for x: -7+log_{3}(4-x)=-6
The solution is x=1