What is the answer to log_{2}(3x^2-4x)=5 ?

The answer to log_{2}(3x^2-4x)=5 is x=4,x=-8/3

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log_{2}(3x^2-4x)=5

lo g_{2} (3 x^{2} - 4 x) = 5

x = 4, x = - \frac{8}{3}

Decimal

x = 4, x = - 2.66666 \dots

Solution steps

lo g_{2} (3 x^{2} - 4 x) = 5

Apply log rules

3 x^{2} - 4 x = 32

Solve

3 x^{2} - 4 x = 32 : x = 4, x = - \frac{8}{3}

x = 4, x = - \frac{8}{3}

lo g_{2} (4 x + 5) = 4

lo g_{\frac{1}{2}} (3 - x) = - 3

lo g_{3} (x^{2} + 1) = 2

lo g_{7} (x) = - 1

lo g_{10} (4 x) + lo g_{10} (3) = lo g_{10} (84)

What is the answer to log_{2}(3x^2-4x)=5 ?
The answer to log_{2}(3x^2-4x)=5 is x=4,x=-8/3
Solve for x: log_{2}(3x^2-4x)=5
The solution is x=4,x=-8/3