What is the answer to log_{7}(x^2-2x-8)=1 ?

The answer to log_{7}(x^2-2x-8)=1 is x=5,x=-3

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log_{7}(x^2-2x-8)=1

lo g_{7} (x^{2} - 2 x - 8) = 1

x = 5, x = - 3

Solution steps

lo g_{7} (x^{2} - 2 x - 8) = 1

Apply log rules

x^{2} - 2 x - 8 = 7

Solve

x^{2} - 2 x - 8 = 7 : x = 5, x = - 3

x = 5, x = - 3

lo g_{2} (x^{2} - 3 x + 10) = 3

lo g_{3} (x + 3) = 2

lo g_{5} (3 x + 5) = 3

ln (x) = 9

15 lo g_{10} (6 x) = - 15

What is the answer to log_{7}(x^2-2x-8)=1 ?
The answer to log_{7}(x^2-2x-8)=1 is x=5,x=-3
Solve for x: log_{7}(x^2-2x-8)=1
The solution is x=5,x=-3