What is the answer to log_{10}(x+12)=log_{10}(x)+log_{10}(12) ?

The answer to log_{10}(x+12)=log_{10}(x)+log_{10}(12) is x= 12/11

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log_{10}(x+12)=log_{10}(x)+log_{10}(12)

lo g_{10} (x + 12) = lo g_{10} (x) + lo g_{10} (12)

x = \frac{12}{11}

Decimal

x = 1.09090 \dots

Solution steps

lo g_{10} (x + 12) = lo g_{10} (x) + lo g_{10} (12)

Apply log rules

x + 12 = x \cdot 12

Solve

x + 12 = x \cdot 12 : x = \frac{12}{11}

x = \frac{12}{11}

Verify Solutions:

x = \frac{12}{11}

True

The solution is

x = \frac{12}{11}

lo g_{3} (x) = - 5

0 = ln (x) + 1

lo g_{4} ((x - 2)^{2}) = - 3

ln (x + 13) - ln (x) = 2

lo g_{x} (32) = - 5

What is the answer to log_{10}(x+12)=log_{10}(x)+log_{10}(12) ?
The answer to log_{10}(x+12)=log_{10}(x)+log_{10}(12) is x= 12/11
Solve for x: log_{10}(x+12)=log_{10}(x)+log_{10}(12)
The solution is x= 12/11