What is the answer to solvefor y,y=ln(3x+4y) ?

The answer to solvefor y,y=ln(3x+4y) is y=-(4\W(-1/(4e^{\frac{3x){4}}})+3x)/4

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solvefor y,y=ln(3x+4y)

solve for

y, y = ln (3 x + 4 y)

y = - \frac{4 W ( - \frac{1}{4 e ^{\frac{3 x}{4}}} ) + 3 x}{4}

Solution steps

y = ln (3 x + 4 y)

f (x) = g (x),

then

a^{f (x)} = a^{g (x)}

e^{y} = e^{l n (3 x + 4 y)}

Simplify

e^{l n (3 x + 4 y)} : 3 x + 4 y

e^{y} = 3 x + 4 y

Solve

e^{y} = 3 x + 4 y : y = - \frac{4 W ( - \frac{1}{4 e ^{\frac{3 x}{4}}} ) + 3 x}{4}

y = - \frac{4 W ( - \frac{1}{4 e ^{\frac{3 x}{4}}} ) + 3 x}{4}

Verify Solutions:

y = - \frac{4 W ( - \frac{1}{4 e ^{\frac{3 x}{4}}} ) + 3 x}{4}

True

The solution is

y = - \frac{4 W ( - \frac{1}{4 e ^{\frac{3 x}{4}}} ) + 3 x}{4}

lo g_{10} (ab x + 1)

7 - lo g_{2} (x) = 3

lo g_{4} (2 x - 6) = 3

lo g_{10} (8 x) - lo g_{10} (1 + x) = 2

x, y = ln (2 x^{2} - 3 y^{2})

What is the answer to solvefor y,y=ln(3x+4y) ?
The answer to solvefor y,y=ln(3x+4y) is y=-(4\W(-1/(4e^{\frac{3x){4}}})+3x)/4