What is the answer to log_{10}(x)+log_{10}(x-99)=2 ?

The answer to log_{10}(x)+log_{10}(x-99)=2 is x=100

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log_{10}(x)+log_{10}(x-99)=2

lo g_{10} (x) + lo g_{10} (x - 99) = 2

x = 100

Solution steps

lo g_{10} (x) + lo g_{10} (x - 99) = 2

Apply log rules

x (x - 99) = 100

Solve

x (x - 99) = 100 : x = 100, x = - 1

x = 100, x = - 1

Verify Solutions:

x = 100

True

, x = - 1

False

The solution is

x = 100

a, x = ln (\frac{a}{s})

lo g_{\frac{1}{3}} (x) = - 3

lo g_{\frac{1}{3}} (x) = - 1

7 lo g_{6} (4 x) + 5 = - 2

2 lo g_{10} (x) - lo g_{10} (x - 16) = 2

What is the answer to log_{10}(x)+log_{10}(x-99)=2 ?
The answer to log_{10}(x)+log_{10}(x-99)=2 is x=100
Solve for x: log_{10}(x)+log_{10}(x-99)=2
The solution is x=100