What is the answer to 25=5x+3ln(x-4) ?

The answer to 25=5x+3ln(x-4) is x=(3\W_{0}((5e^{5/3})/3)+20)/(5)

Solve for x: 25=5x+3ln(x-4)

The solution is x=(3\W_{0}((5e^{5/3})/3)+20)/(5)

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25 = 5 x + 3 ln (x - 4)

x = \frac{3 W _{0} ( \frac{5 e ^{\frac{5}{3}}}{3} ) + 20}{5}

Decimal

x = 5

Solution steps

25 = 5 x + 3 ln (x - 4)

Switch sides

5 x + 3 ln (x - 4) = 25

Move

5 x

to the right side

3 ln (x - 4) = 25 - 5 x

Divide both sides by

3

ln (x - 4) = \frac{25 - 5 x}{3}

f (x) = g (x),

then

a^{f (x)} = a^{g (x)}

e^{l n (x - 4)} = e^{\frac{25 - 5 x}{3}}

Simplify

e^{l n (x - 4)} : x - 4

x - 4 = e^{\frac{25 - 5 x}{3}}

Solve

x - 4 = e^{\frac{25 - 5 x}{3}} : x = \frac{3 W _{0} ( \frac{5 e ^{\frac{5}{3}}}{3} ) + 20}{5}

x = \frac{3 W _{0} ( \frac{5 e ^{\frac{5}{3}}}{3} ) + 20}{5}

Verify Solutions:

x = \frac{3 W _{0} ( \frac{5 e ^{\frac{5}{3}}}{3} ) + 20}{5}

True

The solution is

x = \frac{3 W _{0} ( \frac{5 e ^{\frac{5}{3}}}{3} ) + 20}{5}

lo g_{x + 1} (9) = 2

lo g_{3} (4 x - 7) = 2

lo g_{10} (2 - 5 x) = 1

lo g_{x} (\frac{1}{27}) = 3

lo g_{3} (1 - 2 x) = 1

What is the answer to 25=5x+3ln(x-4) ?
The answer to 25=5x+3ln(x-4) is x=(3\W_{0}((5e^{5/3})/3)+20)/(5)
Solve for x: 25=5x+3ln(x-4)
The solution is x=(3\W_{0}((5e^{5/3})/3)+20)/(5)