What is the answer to log_{10}(2x)+log_{10}(3)=log_{10}(30) ?

The answer to log_{10}(2x)+log_{10}(3)=log_{10}(30) is x=5

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log_{10}(2x)+log_{10}(3)=log_{10}(30)

lo g_{10} (2 x) + lo g_{10} (3) = lo g_{10} (30)

x = 5

Solution steps

lo g_{10} (2 x) + lo g_{10} (3) = lo g_{10} (30)

Move

lo g_{10} (3)

to the right side

lo g_{10} (2 x) = lo g_{10} (30) - lo g_{10} (3)

Apply log rules

2 x = 10

Solve

2 x = 10 : x = 5

x = 5

Verify Solutions:

x = 5

True

The solution is

x = 5

lo g_{10} (x) = 10

lo g_{3} (1 + x) = 2

ln (4 x) = 2 x

lo g_{0.1} (10 x - 7) = - 1

lo g_{3} ((x - 1)^{2}) = 2

What is the answer to log_{10}(2x)+log_{10}(3)=log_{10}(30) ?
The answer to log_{10}(2x)+log_{10}(3)=log_{10}(30) is x=5
Solve for x: log_{10}(2x)+log_{10}(3)=log_{10}(30)
The solution is x=5