What is the answer to ln(2x+1)-1=ln(x-2) ?

The answer to ln(2x+1)-1=ln(x-2) is x=(2e+1)/(e-2)

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ln(2x+1)-1=ln(x-2)

ln (2 x + 1) - 1 = ln (x - 2)

x = \frac{2 e + 1}{e - 2}

Decimal

x = 8.96105 \dots

Solution steps

ln (2 x + 1) - 1 = ln (x - 2)

Apply log rules

2 x + 1 = (x - 2) e

Solve

2 x + 1 = (x - 2) e : x = \frac{2 e + 1}{e - 2}

x = \frac{2 e + 1}{e - 2}

Verify Solutions:

x = \frac{2 e + 1}{e - 2}

True

The solution is

x = \frac{2 e + 1}{e - 2}

ln (\frac{a ^{2}}{x}) = 0

- lo g_{10} (x) = 3.9

9 \times x^{l o g_{3} (x)} = x^{3}

lo g_{2} (5 x) = 4

lo g_{0.5} (x) = 8

What is the answer to ln(2x+1)-1=ln(x-2) ?
The answer to ln(2x+1)-1=ln(x-2) is x=(2e+1)/(e-2)
Solve for x: ln(2x+1)-1=ln(x-2)
The solution is x=(2e+1)/(e-2)