What is the answer to 3+log_{10}(2x+5)=2 ?

The answer to 3+log_{10}(2x+5)=2 is x=-49/20

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3+log_{10}(2x+5)=2

3 + lo g_{10} (2 x + 5) = 2

x = - \frac{49}{20}

Decimal

x = - 2.45

Solution steps

3 + lo g_{10} (2 x + 5) = 2

Move

3

to the right side

lo g_{10} (2 x + 5) = - 1

Apply log rules

2 x + 5 = \frac{1}{10}

Solve

2 x + 5 = \frac{1}{10} : x = - \frac{49}{20}

x = - \frac{49}{20}

Verify Solutions:

x = - \frac{49}{20}

True

The solution is

x = - \frac{49}{20}

lo g_{a} (125) = 3

lo g_{3} (x + 3) = 4

0 = ln (x^{2} - 16)

lo g_{16} (x) = - \frac{3}{4}

- \frac{1}{2} = ln (x)

What is the answer to 3+log_{10}(2x+5)=2 ?
The answer to 3+log_{10}(2x+5)=2 is x=-49/20
Solve for x: 3+log_{10}(2x+5)=2
The solution is x=-49/20