What is the answer to log_{3}(2x)-log_{3}(x+5)=0 ?

The answer to log_{3}(2x)-log_{3}(x+5)=0 is x=5

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log_{3}(2x)-log_{3}(x+5)=0

lo g_{3} (2 x) - lo g_{3} (x + 5) = 0

x = 5

Solution steps

lo g_{3} (2 x) - lo g_{3} (x + 5) = 0

Add

lo g_{3} (x + 5)

to both sides

lo g_{3} (2 x) - lo g_{3} (x + 5) + lo g_{3} (x + 5) = 0 + lo g_{3} (x + 5)

Simplify

lo g_{3} (2 x) = lo g_{3} (x + 5)

Apply log rules

2 x = x + 5

Solve

2 x = x + 5 : x = 5

x = 5

Verify Solutions:

x = 5

True

The solution is

x = 5

2 ln (x) - ln (3) = 0

1 + lo g_{3} (x + 1) = 0

2 x \times ln (x) + x = 0

lo g_{9} (\frac{x - 6}{x + 3}) = 1

lo g_{x - 2} (9) = 2

What is the answer to log_{3}(2x)-log_{3}(x+5)=0 ?
The answer to log_{3}(2x)-log_{3}(x+5)=0 is x=5
Solve for x: log_{3}(2x)-log_{3}(x+5)=0
The solution is x=5