What is the answer to solvefor x,20+47log_{10}(x+2)=65 ?

The answer to solvefor x,20+47log_{10}(x+2)=65 is x=10^{45/47}-2

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solvefor x,20+47log_{10}(x+2)=65

solve for

x, 20 + 47 lo g_{10} (x + 2) = 65

x = 1 0^{\frac{45}{47}} - 2

Decimal

x = 7.06664 \dots

Solution steps

20 + 47 lo g_{10} (x + 2) = 65

Move

20

to the right side

47 lo g_{10} (x + 2) = 45

Divide both sides by

47

lo g_{10} (x + 2) = \frac{45}{47}

Apply log rules

x + 2 = 1 0^{\frac{45}{47}}

Solve

x + 2 = 1 0^{\frac{45}{47}} : x = 1 0^{\frac{45}{47}} - 2

x = 1 0^{\frac{45}{47}} - 2

Verify Solutions:

x = 1 0^{\frac{45}{47}} - 2

True

The solution is

x = 1 0^{\frac{45}{47}} - 2

2 lo g_{10} (x) = lo g_{10} (2 x - 3) + lo g_{10} (3)

lo g_{d} (3) = \frac{1}{2}

lo g_{10} (x) + lo g_{10} (x - 5) = lo g_{10} (6)

x, ln (x) = - 1

3 lo g_{3} (x) = 0

What is the answer to solvefor x,20+47log_{10}(x+2)=65 ?
The answer to solvefor x,20+47log_{10}(x+2)=65 is x=10^{45/47}-2