What is the answer to log_{10}(x+7)=log_{10}(x)+log_{10}(7) ?

The answer to log_{10}(x+7)=log_{10}(x)+log_{10}(7) is x= 7/6

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log_{10}(x+7)=log_{10}(x)+log_{10}(7)

lo g_{10} (x + 7) = lo g_{10} (x) + lo g_{10} (7)

x = \frac{7}{6}

Decimal

x = 1.16666 \dots

Solution steps

lo g_{10} (x + 7) = lo g_{10} (x) + lo g_{10} (7)

Apply log rules

x + 7 = x \cdot 7

Solve

x + 7 = x \cdot 7 : x = \frac{7}{6}

x = \frac{7}{6}

Verify Solutions:

x = \frac{7}{6}

True

The solution is

x = \frac{7}{6}

lo g_{10} (2 x + 50) = 2

lo g_{3} (x) = 0.25

lo g_{3} (5 - x) = 2

lo g_{4} (x + 8) - \frac{1}{2} = 0

ln (x^{2} - 99) = 0

What is the answer to log_{10}(x+7)=log_{10}(x)+log_{10}(7) ?
The answer to log_{10}(x+7)=log_{10}(x)+log_{10}(7) is x= 7/6
Solve for x: log_{10}(x+7)=log_{10}(x)+log_{10}(7)
The solution is x= 7/6