What is the answer to 2ln(x)=ln(18)+ln(x-4) ?

The answer to 2ln(x)=ln(18)+ln(x-4) is x=12,x=6

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2ln(x)=ln(18)+ln(x-4)

2 ln (x) = ln (18) + ln (x - 4)

x = 12, x = 6

Solution steps

2 ln (x) = ln (18) + ln (x - 4)

Apply log rules

x^{2} = 18 (x - 4)

Solve

x^{2} = 18 (x - 4) : x = 12, x = 6

x = 12, x = 6

Verify Solutions:

x = 12

True

, x = 6

True

The solutions are

x = 12, x = 6

y, ln (2 y) = x

2 lo g_{2} (x - 4) + lo g_{2} (2) = 3

lo g_{10} (x^{2}) = - 2

ln (1 - x) = \frac{10}{3} x - 4.16

lo g_{2} (x - 3) = 0

What is the answer to 2ln(x)=ln(18)+ln(x-4) ?
The answer to 2ln(x)=ln(18)+ln(x-4) is x=12,x=6
Solve for x: 2ln(x)=ln(18)+ln(x-4)
The solution is x=12,x=6