What is the answer to log_{10}(5-2x)=1 ?

The answer to log_{10}(5-2x)=1 is x=-5/2

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log_{10}(5-2x)=1

lo g_{10} (5 - 2 x) = 1

x = - \frac{5}{2}

Decimal

x = - 2.5

Solution steps

lo g_{10} (5 - 2 x) = 1

Apply log rules

5 - 2 x = 10

Solve

5 - 2 x = 10 : x = - \frac{5}{2}

x = - \frac{5}{2}

lo g_{4} (10 + 2 x) = 3

lo g_{x + 7} (5 x + 5) = 3

ln (2 + x) = 2

ln (ln (x)) = 1.5

lo g_{7} (3^{2 x} - 3 x + 1) = 1

What is the answer to log_{10}(5-2x)=1 ?
The answer to log_{10}(5-2x)=1 is x=-5/2
Solve for x: log_{10}(5-2x)=1
The solution is x=-5/2