What is the answer to ln(x)+ln(6x)=1 ?

The answer to ln(x)+ln(6x)=1 is x=e^{(1-ln(6))/2}

Solve for x: ln(x)+ln(6x)=1

The solution is x=e^{(1-ln(6))/2}

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ln (x) + ln (6 x) = 1

x = e^{\frac{1 - l n ( 6 )}{2}}

Decimal

x = 0.67308 \dots

Solution steps

ln (x) + ln (6 x) = 1

Apply log rules

x = e^{\frac{1 - l n ( 6 )}{2}}

Verify Solutions:

x = e^{\frac{1 - l n ( 6 )}{2}}

True

The solution is

x = e^{\frac{1 - l n ( 6 )}{2}}

2 x ln (x^{2}) + 2 x = 0

lo g_{2} (x - 1) = \frac{1}{6}

lo g_{10} (x) + lo g_{10} (x + 15) = 2

lo g_{e} (2 x - 1) = - 3

lo g_{4} (x) = x + 2

What is the answer to ln(x)+ln(6x)=1 ?
The answer to ln(x)+ln(6x)=1 is x=e^{(1-ln(6))/2}
Solve for x: ln(x)+ln(6x)=1
The solution is x=e^{(1-ln(6))/2}