What is the answer to log_{2}(4+2^x)=5-x ?

The answer to log_{2}(4+2^x)=5-x is x=2

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log_{2}(4+2^x)=5-x

lo g_{2} (4 + 2^{x}) = 5 - x

x = 2

Solution steps

lo g_{2} (4 + 2^{x}) = 5 - x

f (x) = g (x),

then

a^{f (x)} = a^{g (x)}

2^{l o g_{2} (4 + 2^{x})} = 2^{5 - x}

Simplify

2^{l o g_{2} (4 + 2^{x})} : 4 + 2^{x}

4 + 2^{x} = 2^{5 - x}

Solve

4 + 2^{x} = 2^{5 - x} : x = 2

x = 2

Verify Solutions:

x = 2

True

The solution is

x = 2

lo g_{x} (27) = - 0.5

ln (e^{x} + 1) = x

lo g_{3} (1 - x) = 2

lo g_{3} (5 x + 2) = 3

lo g_{x - 3} (25) = 2

What is the answer to log_{2}(4+2^x)=5-x ?
The answer to log_{2}(4+2^x)=5-x is x=2
Solve for x: log_{2}(4+2^x)=5-x
The solution is x=2