What is the answer to log_{x}(32)=4 ?

The answer to log_{x}(32)=4 is x=2\sqrt[4]{2}

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log_{x}(32)=4

lo g_{x} (32) = 4

x = 242

Decimal

x = 2.37841 \dots

Solution steps

lo g_{x} (32) = 4

Apply log rules

\frac{1}{lo g _{32} ( x )} = 4

Multiply both sides by

lo g_{32} (x)

\frac{1}{lo g _{32} ( x )} lo g_{32} (x) = 4 lo g_{32} (x)

Simplify

1 = 4 lo g_{32} (x)

Switch sides

4 lo g_{32} (x) = 1

Divide both sides by

4

lo g_{32} (x) = \frac{1}{4}

Apply log rules

x = 242

Verify Solutions:

x = 242

True

The solution is

x = 242

lo g_{5} (2 x + 7) = 2

ln (8 x) + 3 = ln (2 x + 6)

lo g_{7} (\frac{3 x}{4} - 2) = 0

lo g_{4} (x - 4) = 3

lo g_{0.4} (20 x) = - 1

What is the answer to log_{x}(32)=4 ?
The answer to log_{x}(32)=4 is x=2\sqrt[4]{2}
Solve for x: log_{x}(32)=4
The solution is x=2\sqrt[4]{2}