What is the answer to log_{3}(2x-5)=-3 ?

The answer to log_{3}(2x-5)=-3 is x= 68/27

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log_{3}(2x-5)=-3

lo g_{3} (2 x - 5) = - 3

x = \frac{68}{27}

Decimal

x = 2.51851 \dots

Solution steps

lo g_{3} (2 x - 5) = - 3

Apply log rules

2 x - 5 = \frac{1}{27}

Solve

2 x - 5 = \frac{1}{27} : x = \frac{68}{27}

x = \frac{68}{27}

lo g_{10} (x + 1) - lo g_{10} (x) = 3

lo g_{e} (x) = x

ln (x - 5) = 0

lo g_{e} (x) = 4

lo g_{10} (x + 14) = lo g_{10} (x) + lo g_{10} (14)

What is the answer to log_{3}(2x-5)=-3 ?
The answer to log_{3}(2x-5)=-3 is x= 68/27
Solve for x: log_{3}(2x-5)=-3
The solution is x= 68/27