What is the answer to log_{2}(3x-7)-5=0 ?

The answer to log_{2}(3x-7)-5=0 is x=13

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log_{2}(3x-7)-5=0

lo g_{2} (3 x - 7) - 5 = 0

x = 13

Solution steps

lo g_{2} (3 x - 7) - 5 = 0

Move

5

to the right side

lo g_{2} (3 x - 7) = 5

Apply log rules

3 x - 7 = 32

Solve

3 x - 7 = 32 : x = 13

x = 13

Verify Solutions:

x = 13

True

The solution is

x = 13

lo g_{0.5} (12 - 8 x) = - 4

3 - lo g_{2} (x - 1) = 0

lo g_{5} (x + 8) = 2

lo g_{10} (x) 0.004 = 2

lo g_{x - 3} (2 x - 18) = 2

What is the answer to log_{2}(3x-7)-5=0 ?
The answer to log_{2}(3x-7)-5=0 is x=13
Solve for x: log_{2}(3x-7)-5=0
The solution is x=13