What is the answer to log_{10}(2x-1)=10 ?

The answer to log_{10}(2x-1)=10 is x=(10^{10}+1)/2

Solve for x: log_{10}(2x-1)=10

The solution is x=(10^{10}+1)/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

lo g_{10} (2 x - 1) = 10

x = \frac{1 0 ^{10} + 1}{2}

Decimal

x = 5000000000.5

Solution steps

lo g_{10} (2 x - 1) = 10

Apply log rules

2 x - 1 = 1 0^{10}

Solve

2 x - 1 = 1 0^{10} : x = \frac{1 0 ^{10} + 1}{2}

x = \frac{1 0 ^{10} + 1}{2}

ln (3 x + 5) = 8

lo g_{x} (0.125) = 3

lo g_{10} (3 x - 4) = 2

\frac{4 ln ( 2 x + 1 )}{2 x + 1} = 0

lo g_{4} (15 + x) = 2

What is the answer to log_{10}(2x-1)=10 ?
The answer to log_{10}(2x-1)=10 is x=(10^{10}+1)/2
Solve for x: log_{10}(2x-1)=10
The solution is x=(10^{10}+1)/2