What is the answer to log_{10}(2x^2)=log_{10}(x^3)-log_{10}(2) ?

The answer to log_{10}(2x^2)=log_{10}(x^3)-log_{10}(2) is x=4

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log_{10}(2x^2)=log_{10}(x^3)-log_{10}(2)

lo g_{10} (2 x^{2}) = lo g_{10} (x^{3}) - lo g_{10} (2)

x = 4

Solution steps

lo g_{10} (2 x^{2}) = lo g_{10} (x^{3}) - lo g_{10} (2)

Apply log rules

x = 4

Verify Solutions:

x = 4

True

The solution is

x = 4

lo g_{4} (\frac{x + 3}{4}) = - 1

lo g_{10} (x) = \frac{1}{5}

lo g_{4} (2 x^{2} + 10 x + 16) = 2

lo g_{10} (2 x) = 2

lo g_{3 x + 2} (2 x + 1) = 0

What is the answer to log_{10}(2x^2)=log_{10}(x^3)-log_{10}(2) ?
The answer to log_{10}(2x^2)=log_{10}(x^3)-log_{10}(2) is x=4
Solve for x: log_{10}(2x^2)=log_{10}(x^3)-log_{10}(2)
The solution is x=4