What is the answer to log_{2}(4x+1)=3 ?

The answer to log_{2}(4x+1)=3 is x= 7/4

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log_{2}(4x+1)=3

lo g_{2} (4 x + 1) = 3

x = \frac{7}{4}

Decimal

x = 1.75

Solution steps

lo g_{2} (4 x + 1) = 3

Apply log rules

4 x + 1 = 8

Solve

4 x + 1 = 8 : x = \frac{7}{4}

x = \frac{7}{4}

ln (x + 1) - ln (x - 1) = \frac{1}{2}

8 lo g_{10} (10 x + 5) = 16

2 (4 x ln (x) + 2 x) = 0

lo g_{12} (x) + lo g_{12} (11 x - 1) = 1

ln (\frac{t - 20}{200}) = - 0.11 t