What is the answer to -log_{10}(x)=2.9 ?

The answer to -log_{10}(x)=2.9 is x= 1/(10^{2.9)}

Solve for x: -log_{10}(x)=2.9

The solution is x= 1/(10^{2.9)}

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- lo g_{10} (x) = 2.9

x = \frac{1}{1 0 ^{2.9}}

Decimal

x = 0.00125 \dots

Solution steps

- lo g_{10} (x) = 2.9

Divide both sides by

- 1

lo g_{10} (x) = - 2.9

Apply log rules

x = \frac{1}{1 0 ^{2.9}}

Verify Solutions:

x = \frac{1}{1 0 ^{2.9}}

True

The solution is

x = \frac{1}{1 0 ^{2.9}}

lo g_{8} (3 x^{2} + 9 x - 20) = 2

lo g_{2} (6 \cdot 2^{2 x + 1} - 6) = x

lo g_{10} (3 x + 1) - lo g_{10} (2 x - 3) = 10

lo g_{0.5} (x) = 4

- 20 = lo g_{10} (x)

What is the answer to -log_{10}(x)=2.9 ?
The answer to -log_{10}(x)=2.9 is x= 1/(10^{2.9)}
Solve for x: -log_{10}(x)=2.9
The solution is x= 1/(10^{2.9)}