What is the answer to 2=-log_{10}(x) ?

The answer to 2=-log_{10}(x) is x= 1/100

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2=-log_{10}(x)

2 = - lo g_{10} (x)

x = \frac{1}{100}

Decimal

x = 0.01

Solution steps

2 = - lo g_{10} (x)

Move

lo g_{10} (x)

to the left side

2 + lo g_{10} (x) = 0

Move

2

to the right side

lo g_{10} (x) = - 2

Apply log rules

x = \frac{1}{100}

Verify Solutions:

x = \frac{1}{100}

True

The solution is

x = \frac{1}{100}

y, - ln (y) = x

20 lo g_{10} (x) = 6

\frac{1}{2} lo g_{4} (x) = 3 lo g_{4} (3)

lo g_{10} (x - 9) = 1

lo g_{4} (x^{2} - 5 x + 2) = 2