What is the answer to log_{2}(x)-1=log_{2}(x-16) ?

The answer to log_{2}(x)-1=log_{2}(x-16) is x=32

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log_{2}(x)-1=log_{2}(x-16)

lo g_{2} (x) - 1 = lo g_{2} (x - 16)

x = 32

Solution steps

lo g_{2} (x) - 1 = lo g_{2} (x - 16)

Apply log rules

x = (x - 16) \cdot 2

Solve

x = (x - 16) \cdot 2 : x = 32

x = 32

Verify Solutions:

x = 32

True

The solution is

x = 32

ln (x) = 5 - x

ln (x) = - 17

ln (2 x) = 7 x + 8

6 ln (x) - 3 = 2 - ln (x)

lo g_{3} (x - 2) = 1

What is the answer to log_{2}(x)-1=log_{2}(x-16) ?
The answer to log_{2}(x)-1=log_{2}(x-16) is x=32
Solve for x: log_{2}(x)-1=log_{2}(x-16)
The solution is x=32