What is the answer to -8log_{10}(3x)+9=11 ?

The answer to -8log_{10}(3x)+9=11 is x= 1/(3\sqrt[4]{10)}

Solve for x: -8log_{10}(3x)+9=11

The solution is x= 1/(3\sqrt[4]{10)}

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- 8 lo g_{10} (3 x) + 9 = 11

x = \frac{1}{3 4 10}

Decimal

x = 0.18744 \dots

Solution steps

- 8 lo g_{10} (3 x) + 9 = 11

Move

9

to the right side

- 8 lo g_{10} (3 x) = 2

Divide both sides by

- 8

lo g_{10} (3 x) = - \frac{1}{4}

Apply log rules

3 x = \frac{1}{4 10}

Solve

3 x = \frac{1}{4 10} : x = \frac{1}{3 4 10}

x = \frac{1}{3 4 10}

Verify Solutions:

x = \frac{1}{3 4 10}

True

The solution is

x = \frac{1}{3 4 10}

x, lo g_{3} (x + y) = z

x = 9 - ln (2 x)

lo g_{- 2 x - 3} (2 x^{2} - 2 x - 15) = 2

x, lo g_{3} (x) = 3

lo g_{10} (x) + lo g_{10} (x + 5) = 2

What is the answer to -8log_{10}(3x)+9=11 ?
The answer to -8log_{10}(3x)+9=11 is x= 1/(3\sqrt[4]{10)}
Solve for x: -8log_{10}(3x)+9=11
The solution is x= 1/(3\sqrt[4]{10)}