What is the answer to roots ln(x^2)-0.7 ?

The answer to roots ln(x^2)-0.7 is x=sqrt(e^{0.7)},x=-sqrt(e^{0.7)}

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roots ln(x^2)-0.7

roots

ln (x^{2}) - 0.7

x = e^{0.7}, x = - e^{0.7}

Solution steps

ln (x^{2}) - 0.7

The roots are the intercepts with the x-axis

(y = 0)

ln (x^{2}) - 0.7 = 0

Move

0.7

to the right side

ln (x^{2}) = 0.7

Apply log rules

x^{2} = e^{0.7}

Solve

x^{2} = e^{0.7} : x = e^{0.7}, x = - e^{0.7}

x = e^{0.7}, x = - e^{0.7}

Verify Solutions:

x = e^{0.7}

True

, x = - e^{0.7}

True

The solutions are

x = e^{0.7}, x = - e^{0.7}

lo g_{2} (7 x + 2) = 4

4 ln (2 x + 3) - 15 = 17

3 (2 x ln (x^{2}) + 2 x) = 0

ln (x) = 3 - x

lo g_{7} (2 x^{2} - 5 x) = 1

What is the answer to roots ln(x^2)-0.7 ?
The answer to roots ln(x^2)-0.7 is x=sqrt(e^{0.7)},x=-sqrt(e^{0.7)}