What is the answer to log_{12}(x^2-8x+16)=0 ?

The answer to log_{12}(x^2-8x+16)=0 is x=5,x=3

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log_{12}(x^2-8x+16)=0

lo g_{12} (x^{2} - 8 x + 16) = 0

x = 5, x = 3

Solution steps

lo g_{12} (x^{2} - 8 x + 16) = 0

Apply log rules

x^{2} - 8 x + 16 = 1

Solve

x^{2} - 8 x + 16 = 1 : x = 5, x = 3

x = 5, x = 3

lo g_{10} (x) 16 = 2

lo g_{x} (9) = 0.5

lo g_{10} (5 - 2 x) = 1

lo g_{8} (x) = \frac{2}{3}

ln (\frac{t - 20}{200}) = - 0.11

What is the answer to log_{12}(x^2-8x+16)=0 ?
The answer to log_{12}(x^2-8x+16)=0 is x=5,x=3
Solve for x: log_{12}(x^2-8x+16)=0
The solution is x=5,x=3