What is the answer to ln(x)+ln(x^2)=4 ?

The answer to ln(x)+ln(x^2)=4 is x=e^{4/3}

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ln(x)+ln(x^2)=4

ln (x) + ln (x^{2}) = 4

x = e^{\frac{4}{3}}

Decimal

x = 3.79366 \dots

Solution steps

ln (x) + ln (x^{2}) = 4

Apply log rules

x = e^{\frac{4}{3}}

Verify Solutions:

x = e^{\frac{4}{3}}

True

The solution is

x = e^{\frac{4}{3}}

lo g_{2} (x - 4) = 4

ln (x) + ln (x^{2}) = 3

2 lo g_{10} (3 - x) = - 1

lo g_{10} (x) 49 = 2

lo g_{10} (x^{2} + 4 x + 17) = 2

What is the answer to ln(x)+ln(x^2)=4 ?
The answer to ln(x)+ln(x^2)=4 is x=e^{4/3}
Solve for x: ln(x)+ln(x^2)=4
The solution is x=e^{4/3}