What is the answer to log_{10}(x)(32)= 5/2 ?

The answer to log_{10}(x)(32)= 5/2 is x=10^{5/64}

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log_{10}(x)(32)= 5/2

lo g_{10} (x) (32) = \frac{5}{2}

x = 1 0^{\frac{5}{64}}

Decimal

x = 1.19708 \dots

Solution steps

lo g_{10} (x) (32) = \frac{5}{2}

Divide both sides by

32

lo g_{10} (x) = \frac{5}{64}

Apply log rules

x = 1 0^{\frac{5}{64}}

Verify Solutions:

x = 1 0^{\frac{5}{64}}

True

The solution is

x = 1 0^{\frac{5}{64}}

ln ((x - 4)^{2}) = 12

lo g_{2 x - 2} (3 x^{2} + 2 x - 17) = 2

lo g_{10} (3 x + 1) = 6

ln (x + 5) = 1

lo g_{5} (x^{2} + 5) = 3

What is the answer to log_{10}(x)(32)= 5/2 ?
The answer to log_{10}(x)(32)= 5/2 is x=10^{5/64}
Solve for x: log_{10}(x)(32)= 5/2
The solution is x=10^{5/64}