What is the answer to solvefor y,ln(xy)+5x=30 ?

The answer to solvefor y,ln(xy)+5x=30 is y=(e^{30-5x})/x {x 0}

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solvefor y,ln(xy)+5x=30

solve for

y, ln (x y) + 5 x = 30

y = \frac{e ^{30 - 5 x}}{x} {x < 0 or x > 0}

Solution steps

ln (x y) + 5 x = 30

Move

5 x

to the right side

ln (x y) = 30 - 5 x

Apply log rules

x y = e^{30 - 5 x}

Solve

x y = e^{30 - 5 x} : y = \frac{e ^{30 - 5 x}}{x}

y = \frac{e ^{30 - 5 x}}{x}

Verify Solutions:

y = \frac{e ^{30 - 5 x}}{x} {x < 0 or x > 0}

The solution is

y = \frac{e ^{30 - 5 x}}{x} {x < 0 or x > 0}

a, ln (a) = ln (b)

x^{2 l o g_{10} (x)} = 100 x^{3}

lo g_{10} (2 x + 4) = 2

4 + lo g_{3} (x - 1) = 2

lo g_{32} (x) = \frac{6}{5}

What is the answer to solvefor y,ln(xy)+5x=30 ?
The answer to solvefor y,ln(xy)+5x=30 is y=(e^{30-5x})/x {x<0\lor x>0}