What is the answer to 4+log_{3}(x-1)=2 ?

The answer to 4+log_{3}(x-1)=2 is x= 10/9

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4+log_{3}(x-1)=2

4 + lo g_{3} (x - 1) = 2

x = \frac{10}{9}

Decimal

x = 1.11111 \dots

Solution steps

4 + lo g_{3} (x - 1) = 2

Move

4

to the right side

lo g_{3} (x - 1) = - 2

Apply log rules

x - 1 = \frac{1}{9}

Solve

x - 1 = \frac{1}{9} : x = \frac{10}{9}

x = \frac{10}{9}

Verify Solutions:

x = \frac{10}{9}

True

The solution is

x = \frac{10}{9}

lo g_{32} (x) = \frac{6}{5}

lo g_{7} (x) = 1.6

x, ln (x y^{3}) = x y

ln (x) - ln (4) = 7

lo g_{10} (x) = \frac{5}{6}

What is the answer to 4+log_{3}(x-1)=2 ?
The answer to 4+log_{3}(x-1)=2 is x= 10/9
Solve for x: 4+log_{3}(x-1)=2
The solution is x= 10/9