What is the answer to log_{10}(x)=1+log_{10}(22-x) ?

The answer to log_{10}(x)=1+log_{10}(22-x) is x=20

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log_{10}(x)=1+log_{10}(22-x)

lo g_{10} (x) = 1 + lo g_{10} (22 - x)

x = 20

Solution steps

lo g_{10} (x) = 1 + lo g_{10} (22 - x)

Apply log rules

x = 10 (22 - x)

Solve

x = 10 (22 - x) : x = 20

x = 20

Verify Solutions:

x = 20

True

The solution is

x = 20

ln (x) + ln (3) = 5

x, ln (2 x) = 5

lo g_{\frac{1}{3}} (x - 2) = - 2

lo g_{3} (x^{2} - 8 x) = 2, x

y, lo g_{2} (y) = x

What is the answer to log_{10}(x)=1+log_{10}(22-x) ?
The answer to log_{10}(x)=1+log_{10}(22-x) is x=20
Solve for x: log_{10}(x)=1+log_{10}(22-x)
The solution is x=20