What is the answer to log_{6}(4x-5)=1 ?

The answer to log_{6}(4x-5)=1 is x= 11/4

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log_{6}(4x-5)=1

lo g_{6} (4 x - 5) = 1

x = \frac{11}{4}

Decimal

x = 2.75

Solution steps

lo g_{6} (4 x - 5) = 1

Apply log rules

4 x - 5 = 6

Solve

4 x - 5 = 6 : x = \frac{11}{4}

x = \frac{11}{4}

lo g_{x + 5} (2 x^{2} + 5 x + 1) = 2

lo g_{9} (x) + lo g_{9} (12) = \frac{1}{2} lo g_{9} (100)

5 lo g_{3} (x + 1) + 6 = 7

lo g_{x} (4) = \frac{- 2}{5}

2 lo g_{10} (7 x) + 1 = 4

What is the answer to log_{6}(4x-5)=1 ?
The answer to log_{6}(4x-5)=1 is x= 11/4
Solve for x: log_{6}(4x-5)=1
The solution is x= 11/4