What is the answer to log_{6}(x^2-x)=1 ?

The answer to log_{6}(x^2-x)=1 is x=3,x=-2

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log_{6}(x^2-x)=1

lo g_{6} (x^{2} - x) = 1

x = 3, x = - 2

Solution steps

lo g_{6} (x^{2} - x) = 1

Apply log rules

x^{2} - x = 6

Solve

x^{2} - x = 6 : x = 3, x = - 2

x = 3, x = - 2

5 ln (x) = - 10

lo g_{4} (x - 5) = 3

74000 = 335000 \cdot lo g_{2} (m)

lo g_{9} (x) = - 2.5

ln (x) + ln (x + 12) = 4

What is the answer to log_{6}(x^2-x)=1 ?
The answer to log_{6}(x^2-x)=1 is x=3,x=-2
Solve for x: log_{6}(x^2-x)=1
The solution is x=3,x=-2