What is the answer to log_{2}(6x+2)=4 ?

The answer to log_{2}(6x+2)=4 is x= 7/3

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log_{2}(6x+2)=4

lo g_{2} (6 x + 2) = 4

x = \frac{7}{3}

Decimal

x = 2.33333 \dots

Solution steps

lo g_{2} (6 x + 2) = 4

Apply log rules

6 x + 2 = 16

Solve

6 x + 2 = 16 : x = \frac{7}{3}

x = \frac{7}{3}

lo g_{- 2} (x) = 3

lo g_{10} (x) + lo g_{10} (x - 21) = 2

lo g_{10} (x) = 7

lo g_{0.2} (x + 4) = - 2

ln (x - 2) = 2